Consider the decomposition the a steel oxide come its elements, whereby M represents a generic metal.

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M203(s)—> 2M(s) + 3/2 O2(g)

info given for Gf(kJ/mol):M203= -6.70M(s)=0O2(g)= 0

what is the standard change in Gibbs energy for rxn as written in front direction? (kJ/mol)What is the equilibrium consistent (K) of this rxn, as created in front direction in ~ 298K?

What is the equilibrium push of O2(g) end M(s) at 298K? (atm)

Concepts and also reason

The distinction between free energy of commodities and totally free energy of reaction is stood for as standard cost-free energy adjust of the reaction.The ratio of concentration of a product come the ratio of concentration that a reactant is stood for as equilibrium constant. The equilibrium constant is expressed as.The equilibrium constant, in regards to partial pressure, is stood for as equilibrium pressure.

FundamentalsThe conventional Gibb’s cost-free energy readjust can it is in calculated by: