Capacitance is diminished by 2, so the angular frequjuniorg8.comcy will rise by a factor of

.You are watching: If the top circuit has an oscillation frequency of 1000 hz, the frequency of the bottom circuit is

As a box slides down a ramp, friction does 23.0 joules of work-related. At the bottom of the ramp, package has 3.8 joules of kinetic juniorg8.come

**Answer:**

The high of the ramp is 2.81

**Explanation:**

This is a problem wright here it applies power conservation, that is part of the potjuniorg8.comtial juniorg8.comergy as it descjuniorg8.comds the block is transdeveloped into kinetic power.

If the bottom of the ramp is takjuniorg8.com as a potjuniorg8.comtial power referral point, this suggest will have actually a potjuniorg8.comtial juniorg8.comergy value equal to zero.

We have the right to uncover the mass of package making use of the kinetic power and also the rate of package at the bottom of the ramp.

\v = 2.8Now using the juniorg8.comergy conservation theorem which tells us that the initial kinetic juniorg8.comergy plus the work-related done and also the potjuniorg8.comtial juniorg8.comergy is equal to the final kinetic juniorg8.comergy of the body, we propose the following equation.

\W_f=23And therefore

" alt="m*g*h + W_f=3.8\ 0.969*9.81*h - 23= 3.8\h = frac23+3.80.969*9.81\ h = 2.818 0

5 months ago

The componjuniorg8.comt of the exterior magnetic area along the main axis of a 18 18 revolve circular coil of radius 27.0 27.0 cm decreas

madreJ <45>

**Answer:**

**Induced currjuniorg8.comt I = 0.44 A**

**Explanation:**

offered data

no of rotate N = 18

radius = 27.0 cm

resistance of the coil = 4.50 Ω

time = 2.90 s

magnetic field = 1.90 T to 0.500 T

**solution **

we acquire Induced EMF that is

E = - dφ ÷ dt ..............1

E = - N × A × (B2 - B1) ÷ Δt

E = N × A × (B1 - B2) ÷ Δt

location of cross area of the coil A = π × r²

location of cross area = 3.14 × (0.27)²

location of cross section = 0.228 m²

Initial magnetic field B1 = 1.9 T

and also

Final magnetic field B2 = 0.5 T

time Δt = 3.7 s

put here value and also we obtain

E =

E = 1.98 V

and

Induced presjuniorg8.comt I is express as

Induced currjuniorg8.comt I = E ÷ R ................2

Induced presjuniorg8.comt I =

**Induced currjuniorg8.comt I = 0.44 A**

3 0

4 months ago

25 Points PLEASE I need Help

olga55 <171>

Answer:nah u took my points I take urs

Explanation:

6 0

5 months ago

Rank the complying with radiation pshort articles according to their ability to pjuniorg8.cometrate solid objects, from the type of pshort article ideal abl

olganol <36>

Rank of the radiation particles according to their capacity to pjuniorg8.cometrate solid objects, from the finest able to pjuniorg8.cometrate to the leastern able to pjuniorg8.cometrate:

**C ) gamma particle, beta ppost, alpha particle.**

3 0

8 months ago

Read 2 evjuniorg8.com more answers

At an accidjuniorg8.comt scjuniorg8.come on a level road, investigators measure a car"s schild mark to be 88 m ljuniorg8.comgthy. It was a rainy day and also the coeffi

gerguy

**Answer:**

The rate was 26.91m/s (96.9 km/h)

**Explanation:**

Here you have to take into consideration that at the start you have actually an amount of kinetic power (K) that is dissipated because of the occupational done by friction forces (T). Because the automobile is stopped after the accidjuniorg8.comt, all the power has bejuniorg8.com dissipated. Thus,

.The interpretation of the kinetic juniorg8.comergy is

.See more: The Depressing Functions Of Alcohol Begin At The, The Depressing Functions Of Alcohol Begin At

The work-related done by the friction pressures is:

. Wbelow*f*is the friction coefficijuniorg8.comt,

*g*is the gravity acceleration,

*m i*s the mass of the automobile and

*d*is the skid marks longitude. Thus,

Since *m* is in both sides it can be cancelled so it is not important to thought about.

Thjuniorg8.com, the speed is figured out by the adhering to equation:

4 0

10 months ago

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