E=kqr2, where k is the Coulomb constant, r is the distance of the charge, and E is the electric field.

You are watching: Calculate the direction of the net electric field at the origin due to these two point charges.

A)

From the given information, the distance of charge q1 from the origin is given by:

r1 = sqrt(0.6002 + 0.8002) =1.0 m

The distance of q2 from the origin:

r2 = sqrt(0.6002 + 02) =0.600 m

E1 = kq/r12 = (9.0 × 109)(4.00 × 10-9)/1.02= 36.0 N/C

E2 = (9.0 × 109)(6.00 × 10-9)/0.6002= 150 N/C

Calculate the x and y components of the electric field at the origin due to the two charges.

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Problem Details

A point charge q1 = -4.00 nC is at the point x = 0.600 meters, y = 0.800 meters, and a second point charge q2 = +6.00 nC is at the point x = 0.600 meters, y = 0.

A) Calculate the magnitude E of the net electric field at the origin due to these two point charges.

B) What is the direction, relative to the negative x-axis, of the net electric field at the origin due to these two point charges.

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